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Year 9 Maths · KS3 notes

Graphs, Pythagoras and percentages

Clear notes with worked examples, then 4 practice questions with answers. Written by Beyond Tutors tutors for the KS3 National Curriculum.

STRAIGHT-LINE GRAPHS: y=mx+cy = mx + c

mm = gradient (steepness), cc = where it crosses the yy-axis.

Gradient from two points = change in yy ÷ change in xx

(1, 3) to (4, 12): 9÷3=39 \div 3 = 3

PYTHAGORAS (right-angled triangles only)

a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse (longest side, opposite the right angle)

Finding cc: square, ADD, square root. 6 and 8 → 100=10\sqrt{100} = 10

Finding a shorter side: square, SUBTRACT, square root. 13 and 12 → 25=5\sqrt{25} = 5

Volume of a prism / cylinder

Volume = area of cross-section × length. Cylinder: πr2h\pi r^2 h

Reverse percentages

After a 20% increase the price is £60. £60 = 120%, so 100% = $60 \div 1.2 = $ £50

Compound interest

original × (multiplier)years^{\text{years}}: 1000×1.12=12101000 \times 1.1^2 = 1210

Practice questions

Try each one, then tap to see the answer and why.

  1. Question 1 · Straight-line graphs

    What is the gradient of the line y=4x−7y = 4x - 7?

    • A−7-7
    • B4
    • C−4-4
    • D7
    Show the answer

    B: 4

    In y=mx+cy = mx + c, the gradient is m=4m = 4.

  2. Question 2 · Straight-line graphs

    A line passes through (1, 3) and (4, 12). What is its gradient?

    • A13\dfrac{1}{3}
    • B4
    • C3
    • D9
    Show the answer

    C: 3

    Gradient = change in yy ÷ change in xx = 9÷3=39 \div 3 = 3.

  3. Question 3 · Pythagoras

    A right-angled triangle has shorter sides 6 cm and 8 cm. How long is the hypotenuse?

    • A14 cm
    • B12 cm
    • C10 cm
    • D48 cm
    Show the answer

    C: 10 cm

    62+82=36+64=1006^2 + 8^2 = 36 + 64 = 100, and 100=10\sqrt{100} = 10.

  4. Question 4 · Volume

    Find the volume of a cylinder with radius 3 cm and height 10 cm. Use π≈3.14\pi \approx 3.14.

    • A94.2 cm³
    • B188.4 cm³
    • C942 cm³
    • D282.6 cm³
    Show the answer

    D: 282.6 cm³

    V=πr2h=3.14×9×10=282.6V = \pi r^2 h = 3.14 \times 9 \times 10 = 282.6 cm³.

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