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Year 8 Maths · KS3 notes

Expanding, factorising and equations

Clear notes with worked examples, then 4 practice questions with answers. Written by Beyond Tutors tutors for the KS3 National Curriculum.

Expanding brackets

Multiply everything inside by the term outside.

5(x+3)=5x+155(x + 3) = 5x + 15 −2(x−4)=−2x+8-2(x - 4) = -2x + 8 (negative × negative = positive)

FACTORISING (the reverse)

Take out the highest common factor.

12x+18=6(2x+3)12x + 18 = 6(2x + 3) x2+7x=x(x+7)x^2 + 7x = x(x + 7)

EQUATIONS WITH x ON BOTH SIDES

Get the x terms on one side first.

7x−4=3x+207x - 4 = 3x + 20

subtract 3x3x: 4x−4=204x - 4 = 20

add 4: 4x=244x = 24

divide by 4: x=6x = 6

Equations with brackets

Expand first. 4(x−2)=2x+64(x - 2) = 2x + 6 → 4x−8=2x+64x - 8 = 2x + 6 → 2x=142x = 14 → x=7x = 7

nth TERM

Difference first, then adjust. 11, 8, 5, 2: difference −3-3, so 14−3n14 - 3n.

Check with n=1n = 1: 14−3=1114 - 3 = 11 ✓

Practice questions

Try each one, then tap to see the answer and why.

  1. Question 1 · Expanding

    Expand and simplify 5(x+3)−2(x−4)5(x + 3) - 2(x - 4).

    • A3x+73x + 7
    • B7x+237x + 23
    • C3x−13x - 1
    • D3x+233x + 23
    Show the answer

    D: 3x+233x + 23

    5x+15−2x+8=3x+235x + 15 - 2x + 8 = 3x + 23. Careful: −2×−4=+8-2 \times -4 = +8.

  2. Question 2 · Negative numbers

    Work out −6×4+15-6 \times 4 + 15.

    • A−39-39
    • B39
    • C9
    • D−9-9
    Show the answer

    D: −9-9

    −6×4=−24-6 \times 4 = -24, then −24+15=−9-24 + 15 = -9.

  3. Question 3 · Factorising

    Factorise fully 12x+1812x + 18.

    • A2(6x+9)2(6x + 9)
    • B6(2x+3)6(2x + 3)
    • C3(4x+6)3(4x + 6)
    • D12(x+18)12(x + 18)
    Show the answer

    B: 6(2x+3)6(2x + 3)

    The highest common factor of 12 and 18 is 6: 6(2x+3)6(2x + 3).

  4. Question 4 · Equations

    Solve 7x−4=3x+207x - 4 = 3x + 20.

    • Ax=4x = 4
    • Bx=6x = 6
    • Cx=2.4x = 2.4
    • Dx=16x = 16
    Show the answer

    B: x=6x = 6

    Subtract 3x3x: 4x−4=204x - 4 = 20. Add 4: 4x=244x = 24, so x=6x = 6.

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